Equation Icon  2 ∂yψ(x,0 ) = κ5(2δρ + 3δp), (283 ) 6 ∂yℬ(x,0 ) = κ25δp, (284 ) 2 ∂y𝒞(x,0 ) = − κ-5δπ, (285 ) 2 κ25 i ∂yℛ (x,0 ) = − 6 δρ − ∂i∂ 𝒞(x,0), (286 )