How could such an eccentric binary millisecond pulsar system form? One possibility is that the
binary system was produced in an exchange interaction in a globular cluster and subsequently
ejected, or the cluster has since disrupted. Statistical estimates [72] of the likelihood of both
these channels are in the range 1–10%, implying that a globular cluster origin cannot be ruled
out.
Another possibility is that the pulsar is a member of an hierarchical triple system with a one solar
mass white dwarf in the 95-day orbit, and a main sequence star in a much wider and highly
inclined orbit which has so far not been revealed by timing. The origin of the high eccentricity is
through perturbations from the outer star, the so-called Kozai mechanism [199]. Formation
estimates based on observational data on stellar multiplicity [293] find that around 4% of all
binary millisecond pulsars are expected to be triple systems [72]. The existence of a single triple
system among the current sample of millisecond pulsars appears to be consistent with this
hypothesis.
If future observations of the proposed optical counterpart confirm it as the binary companion through
spectral line measurements of orbital Doppler shifts, the above triple-system scenario will be ruled out. Such
an observation would favour a hybrid scenario suggested by van den Heuvel [384] in which the white dwarf
and pulsar merge due to gravitational radiation losses. Tidal disruption of the white dwarf in the inspiral
would produce an accretion disk and induce an eccentricity in the orbit of the outer star leaving behind an
eccentric binary system. This idea could naturally account for the high pulsar mass observed in this
system which could arise from accretion of a white-dwarf debris disk following coalescence.
Alternatively, as suggested by Champion et al. [72], the millisecond pulsar might have ablated the
white dwarf companion in a triple system leaving only the unevolved companion in an elliptical
orbit.
http://www.livingreviews.org/lrr-2008-8 | ![]() This work is licensed under a Creative Commons License. Problems/comments to |